It provides an introductory message describing the problem, stores the problem's possible moves and current state, and checks for whether the problem has been successfully solved. (Here we use A because we know that using A to cross both C and D separately is the most efficient.) Suppose in a parallel universe, someone wants to cross from the West Shore to the East Shore at the same you're trying to cross from North to South:There is of course, a brute force way to answer this problem if, as @glugglug asked, the probability of a bridge breaking is not 0.5. As in, you put one foot on the bridge and either it holds or doesn't, so you won't know which bridges are safe until you start. Also, assume we always choose the fastest for the solo-cross. Anybody can answer
So it is not possible for the two slowest (C & D) to cross separately.
By using our site, you acknowledge that you have read and understand our Code Review Stack Exchange is a question and answer site for peer programmer code reviews. Any suggestions for improvement?Why are you creating all these classes if you end up hardcoding all the values anyway?There are two parts especially that I would make more flexible:These things indicate, to me, some things that I would change:Example of factory method: (this can be improved further in various ways)It's quite easy to make these changes which would make your code much cleaner.
@ffao you might be right, but this is still more accurate than my first-instinct guess, which was the probability of a 3 bridge path existing was 3/8ths, since the probability of one of those paths existing was 1/8th and I added all of those together... whoopsIf $p$ is the probability that a bridge is intact, and $q=1-p$, then the probability of being able to cross is $$p^{13}+13p^{12}q+78p^{11}q^2+283p^{10}q^3+677p^9q^4+1078p^8q^5+1089p^7q^6+627p^6q^7+209p^5q^8+38p^4q^9+3p^3q^{10}$$ I did this by computer by checking all $2^{13}$ cases. Anybody can ask a question
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Approach: It is a variation of LIS problem. sequence of crossings so that all four people get across the bridge in Learn more about hiring developers or posting ads with us
This is done by taking persons A, C, & D: C+A+D+A = 5+1+8+1=15.
The bridge and torch problem (also known as The Midnight Train and Dangerous crossing) is a logic puzzle that deals with four people, a bridge and a torch. By clicking “Post Your Answer”, you agree to our To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Very similar (not sure if similar enough for duplicate) to It sounds like the wording is that each bridge has a 50% chance to collapse right before you cross it. Code Review Stack Exchange works best with JavaScript enabled
They start on the same side of the bridge. Four people come to a river in the night. See this puzzle to understand more.
Bridge can hold at max two people at a time.
Our story begins in the 18th century, in the quaint town of Königsberg, Prussia on the banks of the Pregel River.
When Assume that a solution minimizes the total number of crossings.
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